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Prakriteesh (153)

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Olaaa!! Perrrfect answer. 21  [45 rates]

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 a = (u2-u1)/T1 = (u3 - u2)/T2 .........................eq(1)
 
  S1 = u1T1 + 1/2. a. T12
       = u1T1 + 1/2 . (u2-u1)/T1 . T12
       = u1T1 - 1/2 . u1T1  + 1/2.u2T1
       = 1/2. (u1+u2)T1
 
 So,   u1+u2 = 2S1/T1
 Also, u2 - u1 = aT1  from eq(1)
 
  Thus u2 + u1 + u2 - u1 = aT1 + 2S1/T1
            2u2 = at1 +  2S1/T1
              u2 = aT1/2 + S1/T1
 
 Now,
            S2 = u2 + 1/2. a. T22
            S2 = (aT1/2 + S1/T1).T2 + 1/2.aT22
            S2 - S1.T2/T1 = aT1.T2/2 + a.T22/2
   So,  a = 2{S2T1 - S1T2}/(T12T2 + T22T1)
             = 2(T1S2 - T2S1) / T1T2(T1+T2)
           
               
      

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