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krishna.gopal (2397)

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Olaaa!! Perrrfect answer. 381  bad job dude!! I dont approve of this answer! 2  [631 rates]

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X=0, y= 0 and x+y =2 make a right angle triangle of sides 1,1, root(2) with vertecies (1,0),(0,1),(0,0).
The orthocenter of right angled triangle is right angled vertex only = (0,0)
x cordinate of incenter is given by (ax1+bx2+cx3)/(a+b+c)=(1/(2+root(2)))
y cordinate of incenter is given by (ay1+by2+cy3)/(a+b+c)=(1/(2+root(2)))

Hence distance is root(2)/(2+root(2))=1/(root(2)+1)

Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi
 this reply: 5 points  (with Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
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