Electrostatics
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When Q3 is at R net charge at R is Q1+Q3 So potential energy E1=K(Q1+Q3)Q2/d where K=1/4*pi*E0 When Q3 is at S net charge at S is Q2+Q3 So potential energy E2=KQ1(Q2+Q3)/d So change in P.E.=E2-E1 =KQ3(Q1-Q2)/d
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-ADARSH NITK Surathkal |
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