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shakirshafi12 (881)

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Olaaa!! Perrrfect answer. 147  bad job dude!! I dont approve of this answer! 1  [222 rates]

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sin(sin(sin(sinx)))=cos(cos(cos(cosx)))
we are having two functions they are
f(x)=sin(sin(sin(sinx)))
g(x)=cos(cos(cos(cosx)))
f(x) is odd and g(x) is even
 
we will take the function
f(x) and will try to find its maximum and minimum value
the maximum value of f(x) will be
 
f`(x)=cos(sin(sin(sinx)))*cos(sin(sinx))*cos(sinx)*cos x
for cos (sin x)=0
sinx should be equal to pi/2=1.54 which is not possible
hence for maxima=pi/2 +2npi
minima at -pi/2+2npi
 
 
so the maximum value of f(x)=sin(sin(sin(sin(pi/2)))
 
 
let us take the function g(x)
 g`(x)=-sin(cos(cos(cosx)))*-sin(cos(cosx)))*-sin(cosx)*(-sinx)
 g`(x)=sin(cos(cos(cosx)))*sin(cos(cosx)))*sin(cosx)*(sinx)
 
 
if you will double differenciate you will come to know that this function will attain maxima at x=pi/2 and its multiples
and minima at x=0,pi
 
now we see the maxima of f(x) and minima of g(x)
maxima of f(x)=sin(sin(sin(sin(pi/2)))=0.6784 (approx)
minima of f(x)=-0.6784 (approx)
minima of g(x)=cos(cos(cos(cos(0)))=0.6542899(approx)
maxima of g(x)=cos(cos(cos(cos(pi/2)))=0.85755321(approx)
we come to note that at the point of maximas of f(x) and g(x)
g(x) is greater
 at the point of minimas of f(x) and g(x)
g(x) is greater too.
in between we dont have a extremum point otherwise we may have got a solution
 
 
 
hence there is no solution
 
 
i am also showing you the graph of this function




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