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Priyesh (1601)

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hi aatish
see since total k.e remains same
therefore P1V1=P2V2  (bcoz  total k.e = 3/2PV)
also since molecules are inside the box therefore volume occupied is same hence V remains constant
now from ideal gas equations
P1V = nRT1
P2V = 2nRT2  (since molecules are doubled therefore no. of moles is doubled)   
& P1V = P2V   (reason as mentioned in 2nd & 3rd line)
From the above equations P1 = P2 & T2 = T1/2 
 

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