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[Post New]7 May 2007 19:56:05 IST
    Subject: Re:A problem on progressions..................................
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Avinash_Bhat (615)

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Olaaa!! Perrrfect answer. 101  [156 rates]
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(a2 + b2)p2 - 2(ab + bc)p + (b2 + c2)   <=   0
 
     (a2p2 - 2abp + b2)   +   (b2p2 - 2bcp + c2)   <=   0
 
     (ap - b)2   +   (bp - c)2   <=   0
 
     SO : (ap - b)  =  0    and    (bp - c)  =  0
 
    =>  p = b/a         and         p = c/b
 
  a/b = b/c           =>            a,b,c in G.P.           
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