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![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 May 2007 23:34:29 IST
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(a2+b2)p2 - 2(ab+bc)p + (b2+c2) <= 0
(ap-b)2 + (bp-c)2 <= 0
Since LHS >= 0
Hence (ap-b)2 + (bp-c)2 = 0
ap-b=0 and bp-c=0
p = a/b = b/c
Hence a,b,c are in GP.
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Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur
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this reply: 5 points
(with 1 
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