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Ask iit jee aieee pet cbse icse state board experts Discussion Response Post to: Prob in Electrostats, Raman Sir (& other experts too) help pls
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krishna.gopal (2399)

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Olaaa!! Perrrfect answer. 381  bad job dude!! I dont approve of this answer! 2  [632 rates]

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HI Mansi, Lets see how we can approach for such a problem. The symetry of the problem suggests that the four charges will form a square (let say of side a). For general solution lets take length of string to be l, mass and charge of a signgle charge as m & q.
 
Electric force (Fe) on any given charge because of other three
= kq^2/(2a^2)               -------(from charge digonally opposite)
+2*kq^2*sin(45o)/(a^2) -------- (from two adjecent charges. sin(45) comes as only component in digonal direction will add up)
 
Gravitational force on mass=(Fg)=mg
Resultant of both is balanced by tension which acts along the string. Let this string makes an angle theta with vertical. Then
sin(theta)=(a/root(2))/l = Fe/root(Fe2+Fg2)
 
Solve t his to get a.
Minimum distance between charges =a
Maximum distance = root(2)*a
 

Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi
 this reply: 5 points  (with Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
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