IIT JEE , AIEEE Forum - Mathematics , Algebra - $$$$$$$$$ KILLER QUESTION

vishak_great

please check up

from first relation we have 2b=a+c

from second relation we have c^2 = bd

from third relation we have c^2=ae

log_a(c^2) =log_ea+log_ce

log_a ae = log_ea + 1/log_ec

log_ec+log_ac=log_eclog_ea+1

putting c= ^[2]ae and simplifying

we get

(log_ea)^{3 _{= 1}}

_{^{which further means a= b=c=d=e}}

_{^{as a,b,c,d,e, are real}}

_{^{(which is against your first claim)}}

and x=0 and p^{3 _{+ q}3 _{+ r}3 _{= 0}}

please find error if any in the solution