Hello.

I agree with the priority order of shikharbaid.

it is indeed:-

 double bond>triple bond

 

Now, numbering will be from left.

Therefore, the second carbon has only 1 pi-bond.

Thus, it is sp² hybridised as in the case of an alkene.

 

And, the 3rd carbon has two pi-bonds, thus, sp hybridised as in the case af an alkynes and allenes.

 

This is the simplest rule for identifying the hybridisation of carbon.

 

I suppose that you do do FIIT-JEE packages....is it right??