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Discussion Response Post to: RE:TILE PROBLEM(P&C)

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Titun (1467)

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The problem is very clear. I will first try to explain it & then give the solution.

6 nos are chosen from first consecutive 100 natural nos.

The first 3 of the chosen nos give the dimensions of the tiles(i.e its length, breadth & height). The last 3 chosen nos give the length, breadth & height of the rectangular box.

The tile will go into the box if the product of the first 3 nos (i.e the vol. of the tile) is less than the product of the last 3 nos (i.e. the vol. of the box)

There can be 3 cases:

1. The product of the first 3 nos i.e the vol of the tile < the product of the last 3 nos i.e. the vol of the box.

2. The product of the first 3 nos i.e the vol of the tile > the product of the last 3 nos i.e. the vol of the box.

3. The product of the first 3 nos i.e the vol of the tile = the product of the last 3 nos i.e. the vol of the box.

Hence, the reqd probability = 1/3

PLZ TELL ME IF I AM WRONG ANYWHERE

You never know what is enough till you know what is more than enough. Titun

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