the correct ans is option 4 b'coz in 1.e- withdrawing NO2 gp inr + charge same is the case with the Cl (-i effect )of the 3 option bt H3CO is e- donating nd +R effect thus tends to nuetralise the + charge thus its 4(stabler than 2nd also-----without any e- withdrawing or donating gp) hope i m correct
there is no right way 2 do something wrong !!!!!!!!
Moderation Team
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