sign up I login
 advanced
refer a friend - earn nickels!!

Ask & Discuss Questions with Community & Experts

Moderation Team
Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: a verma sum which gave me pleasure
Forum Index -> Mechanics -> View Full Question like the article? email it to a friend.  
Author Message
joyfrancis (1504)

Blazing goIITian

Olaaa!! Perrrfect answer. 236  [398 rates]

joyfrancis's Avatar

total posts: 1801    
offline Offline
Look at the figure for clarity. Let final position of the elevator be the dotted part.
Since the coin is undergoing free fall , the displacement in 1 sec is 4.9m taking g=9.8m/s^2
Displacement of the lift in 1 sec = a/2
and since the coin is initially at 1.8m above the floor the net displacement of the coin is also
1.8+a/2
So
1.8+a/2 = 4.9
a = 6.2m/s^2 = 20.5ft/s^2


There is no better feeling in this world than being a winner!
 this reply: 10 points  (with Olaaa!! Perrrfect answer.   in 2 votes )   [?]
 
You have to be logged on to rate
  
 

Top Offers for goIITians
Correspondence Courses
Brilliant Tutorials
Narayana Institute
Aakash Institute
Classroom/Crash Courses
Narayana - Kota , Delhi , Others
Brilliant Tutorials - Class , Crash
Aakash Institute - Medical , Engg
Online Test Series
Brilliant Tutorials
Narayana Institute
Aakash Institute
Mahesh Tutorials
AMITY      Sri Chaitanya