k..............i 've got an easier way to solve hope this works see lets suppose the four (log 11), (log7) , (log 13), (log 10) all are taken with base 10 (.or any other base) may also work 1. now by the graph of log func we know when both base and the order r greater than 1, the log is positive nd increases in value as the order(the no inside log inc) for the same base 2. log 13>1 (like 1.something) ; log 7<1 =>definitely log 13*log 7<1.................... eg 1.2*0.2=0.24 bt log 11* log 10= log 11>1 thus log10 *log 11 >log 13* log 7 => log 10/log 7> log 13/log 11 =>log_7 (10) >log_11 (13) i feel i cud simplify it
there is no right way 2 do something wrong !!!!!!!!
Moderation Team
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