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[Post New]14 Jan 2007 12:59:34 IST
    Subject: Re:indefinite integral
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edison (4551)

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Olaaa!! Perrrfect answer. 799  [1077 rates]
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 I = (x2.cosx)/(1+sinx)2 .dx   

Integration by parts gives

I = x2cosx/(1+sinx)2 .dx  - (2x.cosx)/(1+sinx)2 .dx

= x2cosx/(1+sinx)2 .dx - 2xcosx/(1+sinx)2 .dx  + 2cosx/(1+sinx)2 .dx

put  (1+sinx) = t, then cosx dx = dt

Now you can proceed.
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