bcoz let velocity of boat =V let velocity of water=U velocity in still water=V velocity on rough day=V-U let it cover distance d ON ROUGH DAY during upsteam time taken T3=d/V-U during downsteam time taken T4=d/V+U total time t1 =T3+T4=2Vd/V2-U2........1 IN STILL WATER total distance =2d so total time t2 =2d/V................2 subtract 1 from 2 u will get t2-t1=2d/V *(1-1/1-U2-V2) here V2= square of V U2= square of U this is always + quantity hence t1>t2
Moderation Team
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