I =
(x
2.cosx)/(1+sinx)
2 .dx
Integration by parts gives
I =
x2cosx/(1+sinx)2 .dx - (2x.integral(cosx/(1+sinx)2 ) .dx)
put (1+sinx) = t, then cosx dx = dt
I=(x^2)((-1)/(1+sinx)) + integral((2x/(1+sinx))dx
Now you can proceed by applyuing by pRTS ON SECOND PART AGAIN
Moderation Team
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