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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 May 2007 00:25:32 IST
Accepted Answer [?]
![[Up]](/templates/default/images/icon_up.gif "[Up]")
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hi the correct ans is 1
here is my soln................
a=log_12 18 = log18/log12
by applying log properties we get................
a=(2log3 + log2)/(log3 + 2log2)
nw b= log_24 54 = log54/log24 = (3log3 + log2)/(3log2 + log3)
nw we ve 2 find ab + 5(a-b)
by solving we get..........ab= [6(log3)^2 + (log2)^2 + 5 log2 log3]/[6(log2)^2 + (log3)^3 + 5 log2 log3]
similarly we get a-b= [(log2)^2 - (log3)2]/[6(log2)^2 + (log3)^2 + 5 log2 log3]
sooo........frm dis we get.........ab+5(a-b) = 1
hope u got it :)
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