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puneet (3568)

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Olaaa!! Perrrfect answer. 620  bad job dude!! I dont approve of this answer! 2  [858 rates]

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total posts: 1966    
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hiiiii
 
Well there is a famous result which is as follows ...
 
0/2 sinmx.cosnx.dx  = (G(m+1/2)G(n+1/2))/2.G((m+n+2)/2)
 
where G is gamma function and it satisfies the following properties ..
 
(i) G(1) = 1  and G(n+1) = n.G(n)
 
(ii) G(n+1) = n! if n is a natural number
 
(iii) G(1/2) =  
 
 
Let me give you some advice ... whenever u see limit between 0 to /2 and sinx , cosx terms ... do try to use this formula .. it is very useful and shud be learnt by heart ..
 
cheers
 

Puneet Agrawal
IIT Delhi
 this reply: 5 points  (with Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
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