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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Jan 2007 20:42:00 IST
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Dear
You can split the force in to two of its components and the vertical component will obviously affect the normal force hence friction force and at the same time the horizontal component will give a translational accelerating you must notice here that
the point of application of the force is passing through the COM hence no moment arm and secondly you must check if R sin 60 = ,< or > Ic /M r ( Ic is the Moment of inertia about COM ) because this will decide the direction of friction if its equal then no friction is needed if greater than then direction of friction will be parallel to the horizontal component of the force if less it will be anti parallel
Now you can form torque and force equation separately to find the value of
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Bhupesh.M |
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