for da second question.........
let
y=10x-10-x/10x+10-x
takin 10-xcommon.......frm both
y=10-x(102x-1)/10-x(102x+1)
y=(102x-1)/(102x+1)
(102x-1)=y102x+y
102x-102xy =1+y
102x(1-y)=(1+y)
102x=1+y/1-y
takin log to base 10 on both sides........
2x=log(1+y/1-y)
x=1/2log(1+y/1-y)
or
f-1(y)=1/2log(1+x/1-x)
hope u got it......
thank u......
Moderation Team
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