|
|
|
|
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 May 2007 22:14:00 IST
|
|
|
Effective acceleration of the bodies aA = g+R/mA aB = g+R/mB
Height attained by the bodies HA = u2 /2aA HB = u2 /2aB
Let mA >mB g+R/mA < g+R/mB u2 /2aA > u2 /2aB HA >HB
Hence the heavier mass attains greater height.
|
|
this reply: 4 points
(with 0 
in 2 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|