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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 May 2007 05:33:02 IST
Accepted Answer [?]
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first question
2 here tension is t
due to earths rotation effective gravity on the ship at equator
== g-rw^2
so tention=m(g-rw^2)
so difference bet tention and earth attr=mg - mrw^2-mg
= - mrw^2
3 tension when moving with a velocity v
if the ship is assumed to move in a circle of radius R with a velocity v then its w1=v/R
this is directed upwards
earth is moving with a ang velocity w directed downwards(earth ratotes west to east)
so resultant ang velocity upwrds = w1-w= (v/ R)-w
so the g-effective for such a ship would be=g-R[ v/ R - W ]^2
so the tention would be======== m*{ g-R[ v/ R - W ]^2 }
this is the tention
reversing the calculation u will be able to find the velocity of the ship by the given tention
plz rate my answer
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