|
|
|
|
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 May 2007 16:08:55 IST
Accepted Answer [?]
|
|
|
If the particle is above earth, g = g0 (1-2h/R) mg = mg0 (1-2h/R) W = W0 (1-2h/R) Where W represents weight. dW/dh = -2W0/R which is independent of h.
If the particle is inside the earth's surface g = g0 (1-h/R) W = W0 (1-h/R) dW/dh = -W0h/R which is independent of h.
|
|
this reply: 5 points
(with 1 
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|