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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: elevator problem
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elessar_iitkgp (2220)

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Olaaa!! Perrrfect answer. 380  [540 rates]

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We will work in the frame of reference of th lift.
Wrt the lift, the acceleration of the coin = a - g = a - 32 ft/s2
Dispacement of the coin wrt the lift = -h = -6 ft
Initial velocity of the coin wrt the lift = 0
Then,
-h = (1/2)(a-g)T2
a = g - (2h/T2)
Substituting the values
a = 20 ft/s2




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