|
|
|
|
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 May 2007 11:35:13 IST
|
|
|
jus temme if ter is any error in this..
cosy = (3 + 5cosx)/ (5 + 3cosx)
cross multiplyin, 5cosy + 3cosxcosy = 3 +5cosx
diff wrt x -5sinydy/dx -3sinxcosy - 3cosxsinydy/dx = -5sinx
hence dy/dx= sinx(5 - 3cosy)/siny(5 + 3cosx)
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|