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[Post New]19 Jan 2007 19:21:42 IST
    Subject: Re:simple harmonic motion (energy concept)
Accepted Answer [?] [Up]
nishant_jain (34)

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Olaaa!! Perrrfect answer. 6  [8 rates]
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total posts: 32    
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Given,
         kA = 50N
1/2KX²=1/2mv²
hence , v=wx
            which means ,
wAcos(wt)=wAsin(wt)
tan(wt)=1
wt=pie/4
Now,
x=A*sin(45)
   A/1.414
we know,
kA=50
k=50/A
Magnitude of force = kx
(50/A) *  (A/1.414)
=50/1.414
 
 this reply: 14 points  (with 2 Olaaa!! Perrrfect answer.   in 4 votes )   [?]
 
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