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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 May 2007 21:54:10 IST
Accepted Answer [?]
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Hi. See fig. Area swept =  /360*pir 2 so area swept by m1 = /360*pi(m 2l/m 1+m 2)^2 and area swept by m2 = /360*pi(m 1l/m 1+m 2)^2 a1/a2 = m22/m12
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Moderation Team
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