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![[Post New]](/templates/default/images/icon_minipost_new.gif) 24 May 2007 10:04:09 IST
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they have to PRATHIMA
as it has to be "inscribed" in the circle....
also angle at each vertice will be 150......RIGHT????
using formula ( n-2)180/n
joining to vetices at the centre we have 12 triangles....
angle subtended at the centre by each triangle will be 30
as it bisects each vertices angle....
using trigo. area of this triangle will be
1/2 ab sinC
where a=b=r=1
C=30
= 1/4
no. of triangles=12
therefore minimum area= 12*1/4=3....
which i think should be the anssssssssss
crt me if wronggggggg
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IIT- Imposible Is This(atleast fr meeeeeeeee) |
this reply: 7 points
(with 1 
in 2 votes ) [?]
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