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Probability Numericals - IV



Dumb question - Q. How . P(A/B1) = ?
And - B1 Letter from AGRA

So, in AGRA there are 3 two letter consecutive word AG, Ga, RA
and A RA is legible
So, there is only one 'RA'
P(A / B1) =
Hard level
Q. 1 Aline of length L is divided (broken ) in to there parts randomly . Find the chance that these parts are the possible sides of
Ans- For to be sides of ,
x > o, y > o

L > X + y

Sum of two sides .> third side

x + y > L -(x + y)
(x + y) > .........................(1)
L - x > X
=> ...................(2)
L - y > y
..................(3)
n(s) x L x L =
(from eqn. L > x + y)
n(A) = Area of ABC

x x
= x
P( E )=
= =
Q. 2 A box contains 6 balls. It is equally likcly that ball is white or black . Two balls are drawn from this bag one is foond black and one is whit.
find the chance that there is 3 black ball in the box .
Ans . 1st ball can be white of black = 2 way
2nd ball can be white of black = 2 way
img ............Total no. of ways in which 6 balls can be white of black
= 2 X 2 X 2 X 2 X 2 X 2 = 26 ways
n(s) = 26
P(B o) = , P(B1) =
P(B 2) = , P(B 3)
P(B4) , P(B 5)
P(B 6) =
A Two balls drawn from bag & of diff. color
P(A / B0) = o [b/c in draw of 2 balls one black ball is there]
P(A / B1) =
P(A / B2) =
P(A / B3) =
P(A / B4) =
P(A / B 5) =
P(A / B6) = 0
P(A) = P(Bo) P(A / Bo) + P(B1) P(A / B1) + P(B2) P(A / B2) + P(B3) P(A / B3) + P(B4) P(A / B4) + P(B5) P(A / B5) + P(B6) P(A / B6)
= +
+
P(B3/ A) =
=
=
P(B3 / A) =

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