Dumb Question: How this derived ? Ans: Let m1 = tan 1 =
m2 = tan 2 =
From fiq, = + 1
= 2 - 1
Orthogonal curves: If angle of intersection of two curves is right angle, two curves are c/d orthogonal curves.
If curves are orthogonal, =
Illustration: Find angle of intersection of curves y = x2 & y = 4 - x2
For intersection points of given curves,
(x2) = 2x
(4 - x2) = - 2x
At x = - ,
= 2 x = 2 & = - 2
Both angles are equal.
Length of Tangent, Sub-Tangent, Normal & sub-Normal: Length of Tangent: Length of segment PT of tangent b/w point of tangent & x-axis is c/d length of tangent.
PT =
Subtangent : Projection of segment PT along x-axis i.e. St c/d subtangent.
Length of Normal : Length of segment PN intercapted b/w point on curve r x-axis. PN =
Subnormal : Projection of segment PN along x-axis i.e. c/d subnormal. SN = |y,
Dumb Question : How these relation derived ?
Ans: Since PT makes angle
 with x-axis, then tan
 =
Subtangent = ST = PS cot
But PS = y 1 & cot
 =
 [see in fig.]
 = cot(90 -
 )
 PS tan
 Subnormal = SN =
Length of tangent = PT =
Length normal = PN =
Illustration : Show that curve y = be x/a . subnormal varies as square of ordinate ?
Ans: [Dumb Question : What is ordinate ?
Ans: y-axis component is c/d ordi i.e. in P(x 1 , y 1 )y 1 is ordinate of point P. y = be x/a ............................................... (i) differentiating curve y = be x/a w.r.t. x.
& Let P(x 1 , y 1 ) lie on curve
Length of subnormal =
So, subnormal varies as square of ordinate.
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