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Discussion Response Post to: limits

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Marshall Eriksen (1586)

Blazing goIITian

total posts: 1312
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Good Sum....I Got 1 as the answer too here is my method :

lim [1+x] log [1+x] - 1 / x

Use Magic(Hospital Bhaiyya's Rule ;) ) ,
using u v product rule for numerator ,

(1)log [1+x] + [1+x]/[1+x]

x > 0
1+x NOT EQUAL to 0
therefore 1+x gets cut

what remains is log [1+x] + 1
1+x = 1
log 1 + 1
0 + 1
1

Sometimes One Dream Is Enough To Light Up The Entire October Sky.... First Year Mechanical Engineering Veermata Jijabai Technological Institute

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