The car flies off tangentially from the outer circle. Let its speed be v at the moment it flies off the circular path. Then at that moment its at a height h above the ground and the base of the embarkment is at a distance hcosec along the incline.
When the car flies off the embarkment, it flies as a projectile projected horizontally from a height h. The quantity R is measured from the base of the embarkment and not from the point vertically below the point of projection.
Range of the car = R2 - h2 cot2 Then, v (2h/g) = (R2 - h2 cot2) v = g(R2 - h2 cot2)/2h