IIT JEE , AIEEE Forum - Mathematics , Algebra

Arjun

see...da question is......da derivative of

y=(1+x)(1+x²)(1+x⁴)(1+x⁸)...............(1+x^{2^n})

y=1/1-x (1-x)(1+x)(1+x²)(1+x⁴)(1+x⁸)...............(1+x^{2^n})

y=1/(1-x)(1-x²)(1+x²)(1+x⁴)(1+x⁸)...............(1+x^{2^n})

again we can use (a+b)(a-b)=a²-b²

so we get

y= (1-x^{4^n})/1-x

use u/v rule....

dy/dx= (-4ⁿx^{4^n-1})(1-x)+(1-x^{4^n})/(1-x)²

u can simplify......i guess itz ryt......

thank u......