|
|
|
|
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 May 2007 19:59:41 IST
|
|
|
hi lolita........wot i think is......since dimensions r the same soo R is proportional to rho. wires r connected in parallel.....n if equivalent resisitivity is denoted by rho then...........1/rho = 1/rho1 + 1/rho2 sooo....v ll get rho = rho1.rho2/(rho1+rho2) sorry if i m wrong......but i think dis is the answer :)
|
this reply: 2 points
(with 0 
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|