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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 May 2007 11:23:58 IST
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I think you can get to the answer by the method of elimination.
When you accelerate the block righwards the shape of the surface of the liquid would change so that the surface becomes perpendicular to the direction of the resultant acceleration.
So the liquid would rise on the left side and fall on the right side , now since the block is closed normal reaction would be there otherwise the liquid would have fallen out and hence giving normal=0.
So this way (c) seems correct.!
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