hiiiii
Let us try to find the point of intersection of the two lines ..
SO let us solve

3x-y-4

3k = 0
and,

3kx+ky-4

3 = 0 simlutaneously
Solving we get x = 2(k2 + 1)/k
and y = 2

3(k
2 - 1)/k
and, now if we find (x)
2 - (y/

3)
2
we get (x)
2 - (y/

3)
2 = 16
so, x2/16 - y2/48 = 1
This is equation of hyperbola and the eccentrity is clearly

(48/16 + 1) = 2
I hope u have got the question ...
cheers