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[Post New]2 Jun 2007 11:34:49 IST
    Subject: Re:Can anyone please reply?
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KAB (1669)

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Olaaa!! Perrrfect answer. 271  [428 rates]
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Given   ylogxlogydx+dy=0
 
So ylogxlogy= -dy/dx
 
or  dy/(ylogy)= -dxlogx
 
Now integrating this we get,
 
log(logy)= -(xlogx-x)+c
 
So the general solution is  x-xlogx-log(logy)+c=0
ADARSH
NITK Surathkal

 this reply: 10 points  (with 2 Olaaa!! Perrrfect answer.   in 2 votes )   [?]
 
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