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the answer should be 3.2mt.(g=10).
letA &B be the bottom & top of the window.
vel. at A=u
vel. at B=v.
time of travel from A to B will be (0.5)/2=0.25.
for motion from A to B ini & final vel. are knwn u&v.accel .is knwn.
t is knwn. we get,u+v=16.
& u-v=2.5
hence.v=8
for motion from B to max ht.,
ini & final vel are 8 & 0.accel. is -10.
we need s.
v^2 -u^2 =2as.
hence,s=3.2mt.
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