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swaprules (176)

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Compd is -->

 CHO-CH2-CH2-CO-CH3

 1->Reduced to n-pentane on clemmenson reduction so carbon skeleton is straight.

 2->dioxime so two carbonyl groups

 3-> Tollens test->aldehyde

 4->iodoform test so in this case->CO-CH3

 B->1->ethyl benzeneàKMnO4àbenzoic acidà(soda lime) benzene

 2->acetaldehyde +acetaldehyde(aldol formation without heating,using dil NaoH or other base) and then clemmenson reduction(zn-hg +Hcl)

 .3->acetone-->(clemmenson reduction)-->2-propanol-->(acid)-->propene

 sorry for writing in text.

 am new to this.


So long Cristiano , and thanx for all the fish! IIT JEE AIR 4468 BITSAT Score 399 AIEEE AIR 2203 SR 170 VITEE AIR 129
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