IIT JEE , AIEEE Forum - Physics , Mechanics

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Let the tension in the string be T.
First we must decide in which direction the frictional force on m₁ will act.
Suppose m₂ moves down. Then
m₂g > T
T>m₁gsin

Which gives
m₂g > m₁gsin

m₂g - m₁gsin

> 0
(2/3)m₁g - m₁g(1/2) > 0
which is true.

Hence the block m₂ moves down. The frictional force on the block m₁ acts down the plane.
m₂g - T = m₂a
T - m₁gsin

-

m₁gcos

= m₁a
Add these two equations and find the acceleration.

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