I think i have a better solution
tr+1-tr =(4r+3)(4r+7)(4r+11)(4r+15)-(4r-1)(4r+3)(4r+7)(4r+11)
=16(4r+3)(4r+7)(4r+11)
=16tr /4r-1
implies 19tr+tr+1=4r.tr+1- 4(r-1)tr
telescoping we get 4n.tn+1-4.0(t1)=20Sn+tn+1-t1
hence Sn=[(4n-1)(4n+3)(4n+7)(4n+11)(4n+15)+3.7.11.15]/20
DONT HESITATE TO ASK FOR ELOBERATION OF MY SOLUTION IF U THINK MY SOLUTION IS OVER ELAGENT