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Ask iit jee aieee pet cbse icse state board experts Discussion Response Post to: A problem on Circular motion
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kghedriu (2333)

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Olaaa!! Perrrfect answer. 423  [532 rates]

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let the coeficient of friction be 'k' and 'w' be the angular speed...instead of theta, i am using @.....
 
well....as friction acts along the tangent to the sphere....u get the range of w wen u vary the direction of fricition....and well.....resolve the forces carefully...and u get the equations as:
 
kg cos@ + k r sin@ w^2 sin@ + r sin@ w^2 cos@= g sin @
 
similarly take the friction to b downwards..u get
     w= [g(sin @ +k cos@)/r sin@( cos@ - k sin@)]^1/2----------(2)
hence the range is between the equations (1) and (2)
 
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