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Rotational Mechanics..Plzz solve...
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I * alpha = torque = mg *(L/2) *sin  therefore (ML^2)/3 *dw/dt = Mg*(L/2)*sin but dw/dt = w *dw/d (as dw/dt = d/dt * dw/d = wdw/d) by seperating variables [0]  [w] w * dw = 3g/2L * [0][pi/2 ] sin therefore after integrating w^2/2 = 3g/2L hence w^2 = 3g/L now N = mg + mw^2(L/2) = mg + 3mg/2 = 5mg/2
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