I * alpha = torque = mg *(L/2) *sin
therefore (ML^2)/3 *dw/dt = Mg*(L/2)*sin
but dw/dt = w *dw/d
(as dw/dt = d
/dt * dw/d
= wdw/d
)
by seperating variables
[0]
[w] w * dw = 3g/2L * [0][pi/2 ] sin
therefore after integrating
w^2/2 = 3g/2L
hence w^2 = 3g/L
now N = mg + mw^2(L/2)
= mg + 3mg/2
= 5mg/2
Moderation Team
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