permutation1
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6 letters 8 boxes so total cases without any conditions is 8P6/2 on applying conditions 1> for 1st row to be empty we get 6 boxes and 6 letters 6!/2. 2>similarly for second row to be empty--> 6!/2 3> 3rd row can neva b empty. so ans is 8!/4-6!. |
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So long Cristiano , and thanx for all the fish! IIT JEE AIR 4468 BITSAT Score 399 AIEEE AIR 2203 SR 170 VITEE AIR 129 |
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