here is the sol of ques 2...

 

let the sum of all the ages be S.

and individual ages be x1,x2,x3............x10

 

now,

 S -- x1 = 82

 S -- x2 = 83

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 S -- x9 = 92

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adding,

9S -- ( S -- x10) =783

=> 8S + x10 = 783 ------------(1)

now we know S -- x10 = p(where p is one of the given sums)----------(2)

adding (1) n(2)

9S = 783 + p

=> S = 87 + p/9

hense p must be multiple of 9 and hence 90..

there fore S=97

hense find x1,x2...   by using privious equations.

plz plz rate me if u got the solutoin and if u liked the method...