|
|
|
|
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Jun 2007 11:22:43 IST
|
|
|
4
See 3^333 can be written as
(3^3)^111
or 27^111
this can be written as
(28-1)^111
now as 28 is divisible by 14 the last term in this expansion that is 1^111 will not be divisible by 14,
hence the remainder will be 1.
|
IIT- Imposible Is This(atleast fr meeeeeeeee) |
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|
Moderation Team
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
