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[Post New]5 Jun 2007 12:28:40 IST
    Subject: Re:Maths problemo
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kghedriu (2333)

Blazing goIITian

Olaaa!! Perrrfect answer. 423  [532 rates]
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total posts: 544    
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answer 4..........
 
well...i think nick is wrong here......
 
3^333= 27^111
         = (28-1)^111
         = (27)*(28^111+28^110+...28^2+28+1)
         = 28k + 27
         = 28k+14+13
         = 14p+13.....    (p belongs to N)
 
hence remainder is 13.. 
 this reply: 10 points  (with 2 Olaaa!! Perrrfect answer.   in 2 votes )   [?]
 
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