IIT JEE , AIEEE Forum - Mathematics , Analytical Geometry

joyfrancis

Hi.

The ans is 6.

The circle touches the axes and its center lies in the first quadrant

.: center has coordinates (r,r)

as per the equation given r=c

also, 4x+3y=12 is a tangent hence its distance from (r,r) should be r only.

.: r = 4c+3c-12/root(16+9)=7c-12/5

c=6

@rahulvedanta

distance of a point x1,y1 from a line ax+by+c=0 is just

ax+by+c/root(a^2+b^2)..it is not plusminus[ax+by+c/root(a^2+b^2)]

logically thinking it is also correct how can a given line and a given point have

two different distances between them