Hi shubham,

 

2)if p were tht real root...then p²+p+ = 0 ;

so, Im() / Im() = -p ; p²+p*Re() = -Re() ;

substitute value of p frm 1st relation into the 2nd relation....ans.

 

1) if u meant lz+1/zl = p(say)....

then check out the ans....

u know lz+1/zl <= lzl+1/lzl ....{let lzl be x}

so,x²-px+1 >= 0

therefore min value of x is ....u find it out